n^2-17n+52=0

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Solution for n^2-17n+52=0 equation: 



n^2-17n+52=0

a = 1; b = -17; c = +52;
Δ = b2-4ac
Δ = -172-4·1·52
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-9}{2*1}=\frac{8}{2}
=4
$


$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+9}{2*1}=\frac{26}{2}
=13
$

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